A particle is moving eastwards with velocity of `5 m//s`. In `10 sec` the velocity changes to `5 m//s` northwards. The average acceleration in this time is.

Options

A. `(1)/(sqrt(2))m//s^(2)` (North-West)
B. `(1)/(sqrt(2))m//s^(2)` (North-East)
C. `sqrt(2)m//s^(2)` (North-West)
D. `sqrt(2)m//s^(2)` (North-East)

Answer

C

Explanation

From first equation of motion, `upsilon = u + at` consider u = 0 and `upsilon = m//s` towards east wards and then consider u = 5 and `upsilon = 5m//s` towards northwards, we get a and `a_(2)` and taking average, we get `a=sqrt(2)ms^(-2)` (North-west)