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The displacement x of a particle along a...

The displacement x of a particle along a straight line at time t is given by `x = a_(0) +a_(1)t + a_(2)t ^(2)`. The acceleration of the particle is

A

`b_(0)`

B

`b_(1)`

C

`b_(2)`

D

`2b_(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

Distance, `x=b_(0)+b_(1)t+b_(2)t^(2)`
Velocity, `upsilon=((dx)/(dt))=b_(1)+2b_(2)t`
Acceleration, `alpha=(d^(2)x)/(dt^(2))=2b_(2)`
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