A bullet of mass `0.1` kg is fired with a speed of 100 `m//sec` , the mass of gun is 50 kg . The velocity of recoil is

Options

A. `0.05ms^(-1)`
B. `0.5 ms^(-1)`
C. `0.1 ms^(-1)`
D. `0.2 ms^(-1)`

Answer

D

Explanation

(d) From the law of conservation of momentum,
total initial momentum= final momentum
`implies m_(1)u_(1)+m_(2)u_(2)=m_(1)v_(1)+m_(2)v_(2)`
`therefore0.1xx0+50xx0=0.1xx100+50(-v_(2))`
`implies 0=10-50v^(2)`
`therefore v_(2)=(10)/(50)=0.2 ms^(-1)`