Two blocks of masses 2 kg and 1 kg are in contact with each other on a frictionless table. When a horizontal force of `3.0` N is applied to the block of mass 2 kg the value of the force of contact between the two blocks is:

Options

A. 4 N
B. 3 N
C. 5 N
D. 1 N

Answer

D

Explanation

(d)
As the block are rigid under the action of a force F, both here move same acceleration.
`a=(F)/(m+M)=(3)/(2+1)=(3)/(3)=1 ms^(-2)`
The force is applied to 2 kg then its action on 1 kg will be
`F_(N)=ma=1xx1=1N`