A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by

Options

A. `sqrt(2) Mg`
B. `sqrt(2) mg`
C. `g sqrt((M+m)^(2)+m^(2))`
D. `gsqrt((M+m)^(2)+M^(2))`

Answer

D

Explanation

(d) `T=mg`
Force on the pulley ( other than from clamp)
`F_("net")=sqrt((T+mg)^(2)+T^(2))`
`=gsqrt((M+m)^(2)+M^(2))`
Since pulley is in equilibrium, clamp will exert the same amount of force in oppsite direction. Or pulley will also exert this much force on clamp.