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In the figure given below masses m and m...

In the figure given below masses m and m' are tied with a thread passing over a pulley, m' is on a frictionlesss horizontal surface. If acceleration due to gravity is g, the acceleration of m' in this arrangement will be

A

g

B

`(m'g)/((m+m'))`

C

`(mg)/(m')`

D

`(mg)/((m-m'))`

Text Solution

Verified by Experts

The correct Answer is:
B
(b)
For mass m
T=ma ..(i)
For mass m'
m'g-T=m'a …(ii)
Solving the Eq. (i) and Eq. (ii)
Acceleration `a=(m'g)/((m+m'))`
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