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A 30kg block rests on a rough horizontal...

A `30kg` block rests on a rough horizontal surface A force of `200N` is applied on the block The block acquires a speed of `4m//s` starting from rest in `2s` What is the value of coefficient of friction ? .

A

`(10)/(3)`

B

`(sqrt(3))/(10)`

C

0.47

D

0.184

Text Solution

Verified by Experts

The correct Answer is:
C
( c) `a=(v)/(t)=(4)/(2)=2ms^(-2) impliesF-f=ma`
or `" "200-muxx30xx10=30xx2`
`therefore" "mu=0.47`
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