A block is gently placed on a conveyor belt moving horizontal with constant speed After `t = 4s` the velocity of the block becomes equal to velocity of the belt If the coefficient of friction between the block and the belt is `mu = 0.2`, then the velocity of the conveyor belt is .

Options

A. `8 ms^(-1)`
B. `4 ms^(-1)`
C. `6 ms^(-1)`
D. `18 ms^(-1)`

Answer

A

Explanation

(a) Due to friction (`a=mug)`, velocity of block will become equal to velocity of belt. Relative motion between two will stop.
`therefore" "v=at=mug=0.2xx10xx4=8 ms^(-1)`