The breaking strength of the cable used to pull a body is 40 N. A body of mass 8 kg is resting on a table of coefficient of friction `mu=0.20`. The maximum acceleration which can be produced by the cable is ( take , `g=ms^(-2)` )

Options

A. `6 ms^(-2)`
B. `3 ms^(-2)`
C. `8 ms^(-2)`
D. `8 ms^(-2)`

Answer

B

Explanation

(b) `a_("max")=(T_("max")-mu mg)/(m)=()40-0.2xx8xx(10)/(8)=3 ms^(-2)`