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Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in the figure. Now the same force F is applied from the right on m. In the two cases the ratio of force of contact between the two blocks will be

A

same

B

`1:2`

C

`2:1`

D

`1:3`

Text Solution

Verified by Experts

The correct Answer is:
B

(b) Acceleration in both the case will be same.l
`N_(1)=ma " but " N_(2)=(2m)a`
`therefore " " (N_(1))/(N_(2))=(1)/(2)`
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