A wooden box of mass 8kg slides down an ...

A wooden box of mass `8kg` slides down an inclined plane of inclination `30^(@)` to the horizontal with a constant acceleration of `0.4ms^(-2)` What is the force of friction between the box and inclined plane ? `(g = 10m//s^(2))` .

36.8N

76.8 N

65.6 N

none of these

Text Solution

Verified by Experts

The correct Answer is:

(a)`mg sin theta-f=ma`(f=force of friction)
or `" "f=m(g sin theta-a)`
`=8(10xx(1)/(2)-0.4)=36.8N`

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