A particle is projected along the line of greatest slope up a rough plane inclined at an angle of `45^(@)` with the horizontal. If the coefficient of friction is `1//2` . Their retardation is:

Options

A. `(g)/(2sqrt(2))`
B. `(g)/(sqrt(2))`
C. `(3g)/(2 sqrt(2))`
D. `(g)/(2)`

Answer

C

Explanation

( c) Acceleration,`a=(g sin theta+ mu g cos theta)`
`=(g)/(sqrt(2))+0.5xxgxx(1)/(sqrt(2)=(3g)/(2sqrt(2))`