Consider the shown arrangement. Assume all surfaces to be smooth. If N represents magnitudes of normal reaction between block and wedge, then acceleration of M along horizontal is equla to

Options

A. `(N sin theta)/(M)` along + veX-axis
B. `(N cos theta)/(M)` along - veX-axis
C. `(N sin theta)/(M)` along - veX-axis
D. `(N sin theta)/(m+M)` along - veX-axis

Answer

C

Explanation

( c) Wedge move due to horizontal component of normal reaction.
Thus `" " a=(N_(H))/(M)=(N sin theta)/(M)" " `(along-ve X-axis)