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A block of mass m slides down an incline...

A block of mass m slides down an inclined plane which makes an angle `theta` with the horizontal. The coefficient of friction between the block and the plane is `mu`. The force exerted by the block on the plane is

A

`mu mg`

B

`mu mg sin theta`

C

`mu (mg sin theta-mg cos theta)`

D

`mg sin theta`

Text Solution

Verified by Experts

The correct Answer is:
D

(d) Block is a rest. Hence, `f=mg sin theta`
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