If a body looses half of its velocity on penetrating 3 cm in a wooden block, then how much will it penetrate more before coming to rest?

Options

A. 1 cm
B. 2 cm
C. 3 cm
D. 4 cm

Answer

A

Explanation

(a) Assuming the resistance force or retardation to be constant.
`((v)/(2))^(2)=v^(2)-2as_(1)`…….(i)
`0=((v)/(2))^(2)-2as_(2)`………(ii)
Solving these two equations, we get, `s_(2)=(s_(1))/(3)=1 cm`