A block of mass 5 kg resting on a horizontal surface is connected by a cord, passing over a light frictionless pulley to a hanging block of mass 5 kg. The coefficient of kinetic friction between the block and surface is 0.5. Tension in the cord is (take, `g=9.8ms^(-2)`)

Options

A. 49 N
B. zero
C. 36.75 N
D. 12.75 N

Answer

C

Explanation

( c) `a=("Net pulling force")/("Total mass")`
`=(5g-0.5xx5xxg)/(10)=(g)/(4)`
Equation of motion for the hanging mass will be,
`5g-T=5a=(5g)/(4)`
`therefore" " T=(15)/(4)g=(15xx9.8)/(4)=36.75 N`