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A wedge of mass 2m and a cube of mass m ...

A wedge of mass 2m and a cube of mass m are shown in figure. Between cube and wedge, there is no friction. The minimum coefficient of friction between wedge and ground so that wedge does not move is:

A

0.1

B

0.2

C

0.3

D

0.4

Text Solution

Verified by Experts

The correct Answer is:
B

(b)`a=g sin theta=(g)/(sqrt(2))`

`a_(H)=a_(V)=(g)/(sqrt(2))xx(1)/(sqrt(2))=(g)/(2)`
`(N)/(sqrt(2))=(mg)/(2)`…….(i)
`mg-(N)/(sqrt(2))=(mg)/(2)`……(ii)
`N'=(N)/(sqrt(2))+2 mg`……(iii)
`muN'=(N)/(sqrt(2))`…….(iv)

Solving above four equations, we get
`mu=0.2`
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