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Block B moves to the right with a consta...

Block B moves to the right with a constant velocity `v_(0)`. The velocity of body A relative to B is

A

`(v_(0))/(2)`, towards left

B

`(v_(0))/(2)`, towards right

C

`(3v_(0))/(2)`, towards left

D

`(3v_(0))/(2)`, towards right

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `T_(B)=3N " and " T_(A)=2N`
`therefore" " v_(A)=(T_(B))/(T_(A)).v_(B)=(3)/(2)v_(0)`(towards right)
`therefore" " v_(AB)=(3v_(0))/(2)-v_(0)=(v_(0))/(2),` towards right.
In such cases, velocity and acceleration are in the ration of tensions.
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