A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

Options

A. 0.98 N vertically downwards
B. 0.49 N vertically downwards
C. 9.8 N vertically downwards
D. 0.49 N vertically upwards

Answer

B

Explanation

(b) Given, m=0.05 kg
We know that, net force acting on a stone,
`f_(g)=mg=0.05xx(-9.8)="-0.49N"`
=0.49 N vertically downwards