A balloon starting from rest ascends vertically with uniform acceleration to a height of 100m is 10s. The force on the bottom of the balloon by a mass of 50 kg us (`g=ms^(-2)`)

Options

A. 100 N
B. 300 N
C. 600 N
D. 400 N

Answer

C

Explanation

( c) Given that, h=100m and t=10s
From equation of motion,
`h=(1)/(2) at^(2)`
`a=(2h)/(t^(2))=(2xx100)/((10)^(2))=2 ms^(-2)`
Now, `F=50(10+2) implies F=600 N`