A machine gun fires a bullet of mass 40 g with a velocity `1200 ms^-1`. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can be fire per second at the most?

Options

A. Only one
B. Three
C. Can fire any number of bullets
D. `144xx48`

Answer

B

Explanation

(b) Given that,` m_(b)=40g, v_(b)=1200 ms^(-1)`
F=144 N
`therefore F=ma=(m_(v)v_(b))/(t)`
`implies 144=(40xx1200)/(1000)xxn implies n=3`