A monkey of 25 kg is holding a vertical rope. The rope does not break if a body of mass 30 kg is suspended with the rope exceeds 30 kg. What will be the maximum acceleration with which the monkey can climb up along the rope ? ( Take ,`=10 ms^(-2)`)

Options

A. `2 ms^(-2)`
B. `2.5 ms^(-2)`
C. `3 ms^(-2)`
D. `4 ms^(-2)`

Answer

A

Explanation

(a) The maximum weight which can be suspended with the rope without breaking it =30 kg-wt.
`=30xx10=300N`
`therefore 300N=mg+ma`
`implie ma=300- mg`
`=300-25xx10=50N`
`implies a=(50)/(m)=(50)/(25)=2 ms^(-2)`