A harmonic oscillation of force constant `4xx10^(6) Nm^(-1)` and amplitude 0.01 m has total energy 240 J. What is maximum kinetic energy and minimum potential energy?

Explanation

To solve the problem, we need to find the maximum kinetic energy and minimum potential energy of a harmonic oscillator given the force constant and amplitude.

### Step 1: Understand the relationship between total energy, maximum kinetic energy, and minimum potential energy.
In a harmonic oscillator, the total energy (E) is the sum of the maximum kinetic energy (KE_max) and the minimum potential energy (PE_min):
\[ E = KE_{max} + PE_{min} \]

### Step 2: Calculate the maximum kinetic energy.
The maximum kinetic energy in a harmonic oscillator can be calculated using the formula:
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