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A particle excutes SHM, at what value of...

A particle excutes SHM, at what value of displacement are the kinetic and potential energies equal?

Text Solution

Verified by Experts

We know that `KE=(1)/(2)momega^(2)(A^(2)-x^(2))`
and `U=(1)/(2)momega^(2)x^(2)`
Since,K=U
`(1)/(2)momega^(2)(A^(2)-x^(2))=(1)/(2)momega^(2)x^(2) "or " 2x^(2)=A^(2)`
or `x=(A)/(sqrt(2))=0.707A`
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