Home
Class 11
PHYSICS
The amplitude and the time period in a S...

The amplitude and the time period in a S.H.M. is 0.5 cm and 0.4 sec respectively. If the initial phase is `pi//2` radian, then the equation of S.H.M. will be

A

y=0.5 sin 5`pit`

B

y=0.5 sin 4`pit`

C

y=0.5 sin 2.5`pit`

D

y=0.5 cos `5pit`

Text Solution

Verified by Experts

The correct Answer is:
D
`y=a"sin"(omegat+phi)=a"sin"((2pi)/(T)+phi)`
`implies y=0.5 "sin" ((2pi)/(0.4)t+(pi)/(2))`
`y=0.5 "sin"(5pit+(pi)/(2))=0.5 "cos" 5pit`
Promotional Banner

Similar Questions

Explore conceptually related problems

The amplitude and time period in SHM are 0.8 cm and 0.2 sec respectively. If the initial phase is pi//2 radian, then the equation representing SHM is -

The amplitude and the periodic time of a S.H.M. are 5 cm and 6 sec respectively. At a distance of 2.5 cm away from the mean position, the phase will be

Define amplitude of S.H.M. ?

Define amplitude of S.H.M. ?

Given equation of S.H.M. is y = 10 sin(20t+0.5). The initial phase is

The equation of S.H.M. with amplitude 4m and time period 1/2 s with initial phase pi//3 is x =