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Velocity at mean position of a particle ...

Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be

A

`(v)/(2)`

B

`(v)/(sqrt(2))`

C

`(sqrt(3))/(2)v`

D

`(sqrt(3))/(4)` v

Text Solution

Verified by Experts

The correct Answer is:
C
Velocity at mean position `v=aomega` velocity at a distance of half amplitude
`v'=omegasqrt(a^(2)-y^(2))=omegasqrt(a^(2)-(a^(2))/(4))=(sqrt(3))/(2)aomega=(sqrt(3))/(2)v`
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