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The maximum acceleration of a simple har...

The maximum acceleration of a simple harmonic oscillator is `a_(0)` and maximum velocity is `v_(0)`. What is the displacement amplitude?

A

`(v_(0)^(2))/(a_(0))`

B

`a_(0)v_(0)`

C

`(a_(0)^(2))/(v_(0))`

D

`(1)/(a_(0)v_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
`omega^(2)A=a_(0) " "…(i)`
`omegaA=v_(0) " "…(ii)`
On solving , we get `A=(v_(0)^(2))/(a_(0))`
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