Home
Class 11
PHYSICS
For a particle in S.H.M. if the amplitud...

For a particle in `S.H.M.` if the amplitude of displacement is `a` and the amplitude of velocity is `v` the amplitude of acceleration is

A

va

B

`(v^(2))/(a)`

C

`(v^(2))/(2a)`

D

`(v)/(a)`

Text Solution

Verified by Experts

The correct Answer is:
B
We know that , `v_("max")=aomega` and
Maximum acceleration `=omega^(2)a" "[because x=a]`
`=((v)/(a))^(2)a=(v^(2))/(a)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The two particles performing S.H.M. have a phase difference of pi . If the amplitude of second particle is three times the amplitude of first particle, then the amplitude of resultant motion will be

A particle executing SHM of amplitude a has displace ment (a)/(2) at t=(T)/(4) and a negative velocity. The epoch of the particle is

A particle executes a linear S.H.M. of amplitude 8 cm and period 2s. The magnitude of its maximum velocity is

The potential energy of a particle execuring S.H.M. is 2.5 J, when its displacement is half of amplitude. The total energy of the particle be

The potential energy of a particle executing S H M is 25 J. when its displacement is half of amplitude. The total energy of the particle is

A particle exectues a linear S.H.M. of amplitude 2 cm. When it is at 1cm from the mean position, the magnitudes of its velocity and acceleration are equal. What is its maximum velocity ? [sqrt(3)=1.732]

The maximum velocity of a particle performing a S.H.M is v. If the periodic time is made 1//3 rd and the amplitude is doubled, then the new maximum velocity of the particle will be

A particle executes SHM with an amplitude of 0,2 m . Its displacement when its phase is 90^(@) is

A particle is executing S.H.M. with amplitude 'A' and maximum velocity V_(m) . The displacement at which its velocity is half of the maximum velocity is