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A particle is vibrating in a simple h...

A particle is vibrating in a simple harmonic motion with an amplitude of 4 cm . At what displacement from the equilibrium position, is its energy half potential and half kinetic

A

1 cm

B

`sqrt(2)` cm

C

3 cm

D

`2sqrt(2)` cm

Text Solution

Verified by Experts

The correct Answer is:
D

`U=K " or "U=(E)/(2)`
`therefore (1)/(2)Kx^(2)=(1)/(2)((1)/(2)KA^(2))`
i.e., at `x=+-(A)/(sqrt(2)),U=K`
and this situation will occur for four times in one complete period.
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