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The amplitude of a particle executing SH...

The amplitude of a particle executing SHM is made three-fourth keeping its time period constant. Its total energy will be

A

16 E

B

8 E

C

4 E

D

E

Text Solution

Verified by Experts

The correct Answer is:
D
(d) As `E=(1)/(2)momega^(2)A^(2)`
or `E=(1)/(2)m((2pi)/(T))^(2)(A)^(2) " "(because omega=(2pi)/(T))`
As `T'=2T" "A'=2A`
`therefore E'=(1)/(2)mxx(1)/(4)((2pi)/(T))^(2)xx4(A)^(2)=E`
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