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The length of a simple pendulum executin...

The length of a simple pendulum executing simple harmonic motion is increased by `21%`. The percentage increase in the time period of the pendulum of increased length is

A

`0.11`

B

`0.21`

C

`0.42`

D

`10.5`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) As, `T=2pisqrt((l)/(g))implies (DeltaT)/(T)=(1)/(2)(Deltal)/(l)`
Given , `(Deltal)/(l)=21%`
`implies (DeltaT)/(T)=(1)/(2)xx 21%=10.5 %`
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