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A man measures the period of a simple pe...

A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. if the lift accelerates upwards with an acceleration g/4, then the period of the pendulum will be

A

T

B

`(T)/(4)`

C

`(2T)/(sqrt(5))`

D

`2Tsqrt(5)`

Text Solution

Verified by Experts

The correct Answer is:
C
(c) In stationary lift, `T=2pisqrt((l)/(g))`
In upward motion of lift,
`T'=2pisqrt((l)/((g+a)))` (a=acceleration of lift)
`implies (T')/(T)=sqrt((g)/(g+a)) =sqrt((g)/((g+(g)/(4))))=sqrt((4)/(5))impliesT'=(2T)/(sqrt(5))`
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