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In a simple pendulum the period of oscil...

In a simple pendulum the period of oscillation `(T)` is related to the length of the pendulum `(L)` as

A

`(l)/(T)` =constant

B

`(l^(2))/(T)` =constant

C

`(l)/(T^(2))` =constant

D

`(l^(2))/(T^(2))` =constant

Text Solution

Verified by Experts

The correct Answer is:
C
(c) `T=2pisqrt((l)/(g))implies (l)/(T^(2))=(g)/(4pi^(2))`=constant
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