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A particle executing SHM of amplitude ...

A particle executing SHM of amplitude 4 cm and `T=4 s` .The time taken by it to move from positive extreme position to half the amplitude is

A

1 s

B

`(1)/(3)` s

C

`(2)/(3)` s

D

`sqrt((2)/(3))` s

Text Solution

Verified by Experts

The correct Answer is:
C
(c)Equation of motion , `y= a"cos"omegat`
`implies(a)/(2)=a "cos"omegatimpliesomegat=(pi)/(3)`
`implies (2pit)/(T)=(pi)/(3)impliest=((pi)/(3)xxT)/(2pi)=(4)/(3xx2)=(2)/(3) s`
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