A light spring of force constant `8 Nm^(-1)` is cut into two equal halves and the two are connected in parallel, the equivalent force constant of the system is

Options

A. `16 Nm^(-1)`
B. `32 Nm^(-1)`
C. `8 Nm^(-1)`
D. `24 Nm^(-1)`

Answer

B

Explanation

(b) `k prop (1)/(l)` hence, k of individual halves will be `16 Nm^(-1)` . When they are connected in parallel, effective value of k will becomes `32 N m^(-1)`.