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In order that the resultant path on supe...

In order that the resultant path on superimposing two mutually perpendicular SHM be a circle, the conditions are that

A

the amplitudes on both SHM should be equal and they should have a phase difference of `(pi)/(2)`

B

the amplitude should be in the ratio 1:2 and the phase difference should be zero

C

the amplitude should be in the ratio 1:2 and the phase difference should be `(pi)/(2)`

D

the amplitudes should be equal and the phase difference should be zero

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Suppose `x=A "sin" omegat` and `y= A"cos"omegat`
Then by squaring and adding these two equations , we get ` x^(2)+y^(2)=A^(2)`
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