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Two bodies (M) and (N) of equal masses a...

Two bodies (M) and (N) of equal masses are suspended from two separate massless springs of spring constants (k_1) and (k_2) respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of (M) to the of (N) is.

A

`(k_(1))/(k_(2))`

B

`sqrt((k_(1))/(k_(2)))`

C

`(k_(2))/(k_(1))`

D

`sqrt((k_(2))/(k_(1)))`

Text Solution

Verified by Experts

The correct Answer is:
D
(d)`omega_(1)A_(1)=omega_(2)A_(2)`
`(A_(1))/(A_(2))=(omega_(2))/(omega_(1))=sqrt((k_(2))/(k_(1)))" "("as "omega=sqrt((k)/(m)))`
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