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A particle of mass 2 kg moves in simple ...

A particle of mass `2 kg` moves in simple harmonic motion and its potential energy `U` varies with position `x` as shown. The period of oscillation of the particle is

A

`(2pi)/(5)` s

B

`(2sqrt(2)pi)/(5) s`

C

`(sqrt(2)pi)/(5)` s

D

`(4pi)/(5)` s

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `(1)/(2)kA^(2)=1J`
`therefore k=(2)/(A^(2))=(2)/((0.4)^(2))=(25)/(2) Nm^(-1)`
`T=2pisqrt((m)/(k))=2pisqrt((2)/((25//2)))=(4pi)/(5)s`
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