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A cubical block of mass M vibrates horiz...

A cubical block of mass M vibrates horizontally with amplitude of 4.0 cm and a frequency of 2.0 Hz. A small block of mass is placed on the bigger block. In order that the smaller block does not side on the bigger block, the minimum value of the coefficient of static friction between the two blocks is (0.16x). Find the value of x(Take `pi^(2)`=10 and g=10m/`s^(2)`)

A

8

B

12

C

4

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
(c) `mug gt ` maximum acceleration in SHM ` gt omega^(2)A`
`therefore mu gt (omega^(2)A)/(g) implies mu gt ((2pif)^(2)xx A)/(g)`
`implies mu gt ((2xx3.14xx2)^(2)xx 4xx 10^(-2))/(10)`
`implies mu gt 0.631 ~~ 0.64`
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