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A particle under the action of a force h...

A particle under the action of a force has a period of `3s` and under the action of another force it has a period `4sec` in `SHM`. What will be its period under the combined action of both forces in the same direction?

A

7 s

B

5 s

C

2.4 s

D

0.4 s

Text Solution

Verified by Experts

The correct Answer is:
C
(c) `T=2pisqrt((m)/(k))` or `T prop (1)/(sqrt(k))`
T has increased `(4)/(3)` times . Hence , `k'=(9)/(16)k`
When both are combined,
`k_("net")=k+k'=(25)/(16)k` or `(25)/(16)` times
Hence, new time period will becomes `(4)/(5)` times of 3 s or 2.4 s.
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