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A particle is in linear SHM of amplitude...

A particle is in linear SHM of amplitude A and time period T. If v refers to its average speed during any interval of T/3 , then the maximum possible value of v is

A

`(3sqrt(3))/(T)A`

B

`(sqrt(3)A)/(T)`

C

`(2sqrt(3))/(T)A`

D

`(3A)/(T)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `(T)/(3)` means `120^(@)` in reference circle. Maximum posible value of V is near position between P and Q

`therefore V=("Distance")/("Time")=(sqrt(3)A)/((T//3))=(3sqrt(3)A)/(T)`
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