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The system shown in figure is in equilib...

The system shown in figure is in equilibrium . The mass of the container with Liquid is M, density of liquid in the container is `rho` and the volume of the block is V. If the container is now displaced downwards through a distance `x_(0)` and released such that the block remains well inside the liquid then during subsequent motion

A

time period of SHM of the container will be `2pisqrt((M)/(k))`

B

time period of SHM of the container will be `2pisqrt((M+rhoV)/(k))`

C

amplitude of SHM of the container is `x_(0)`

D

amplitude of SHM of the container is `2x_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `M_(e)`= Mass of container + `("Upthrust")/(g)`
`M+(rhoVg)/(g)=M+rhoV`
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