Home
Class 11
PHYSICS
Assertion : If a pendulum is suspended i...

Assertion : If a pendulum is suspended in a lift and lift accelerates upwards, then its time period will decrease.
Reason : Effective value of g will be `g_(e)=g+a`

A

If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.

B

If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.

C

If Assertion is true but Reason is false.

D

If Assertion is false but Reason is true.

Text Solution

Verified by Experts

The correct Answer is:
A

(a) T=2pidqrt((l)/(g_(e))`
Here, `g_(e)=g+a` , if the lift accelerates upwards.
Promotional Banner

Similar Questions

Explore conceptually related problems

If a simple pendulum is suspended in a lift and lift is moving downwards an acceleration, time period of simple pendulum

Assertion:- If barometer is acceleratated upwards, the level of mercury in the tube of barometer will decrease. Reason:- The effective value of g will increase, so upthrust increase.

The period of a simple pendulum inside a stationary lift is T. The lift accelerates upwards with an acceleration of g/3 . The time period of pendulum will be

Assertion : If a pendulum falls freely, then its time period becomes infinite. Reason : Free falling body has acceleration, equal to 'g'.

A simple pendulum is oscillating in a lift. If the lift starts moving upwards with a uniform acceleration, the period will

The time period of a simple pendulum inside a stationery lift is T . If the lift accelerates upwards uniformly with (g)/(4) , then its time period would be

A man of mass 60 kg is in a lift and lift is accelerating upwards with acceleration 4 m//s^(2) . Calculate effective weight of man in lift.

Time period of a simple pendulum in a freely falling lift will be

(i) Calculate the length of a second's pendulum. (ii) If this pendulum is mounted in a lift which accelerates upwards at 2.8 ms^(-2) , by what factor does its period of oscillation change from the original value ? Given g on earth =9.8 ms^(-2) .