Home
Class 11
PHYSICS
Assertion : In x-=3+4 "cos" omegat , amp...

Assertion : In x-=3+4 `"cos" omegat` , amplitude of oscillation is 4 units.
Reason : Mean position is at x=3.

A

If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.

B

If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.

C

If Assertion is true but Reason is false.

D

If Assertion is false but Reason is true.

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `X=x-4=4"cos"omegatimpliesX=0 " at " x=3`
Promotional Banner

Similar Questions

Explore conceptually related problems

Assertion : The amplitude of oscillation can never be infinite. lt brgt Reason : The energy of oscillator is continuously dissipated.

Assertion : In x=5-4 "sinomegat , motion of body is SHM about the mean position x=5 Reason Amplitude of oscillation is 9.

By means of plotting find the amplitude of the oscillation resulting from the addition of the following three oscillations of the same direction: xi_(1) = a cos omegat, xi_(2) = 2a sin omegat, xi_(3) = 1.5 a cos (omegat + pi//3) .

The particle is moving such that its displacement along x-axis as a function of time is given by x(x -6) = 1 - 10 cos omegat . Find amplitude, time period and mean position.

The position of S.H.M. is given by x=2[√3sin πt +cos πt] . The amplitude of motion is [ x is in metre and symbols have the usual meaning]

A particle of mass (m) is executing oscillations about the origin on the (x) axis. Its potential energy is V(x) = k|x|^3 where (k) is a positive constant. If the amplitude of oscillation is a, then its time period (T) is.

Using graphical means find an amplitude a of oscillations resulting from the superposition of the following oscillations of the same direction : (a) x_(1)=3.0 cos (omegat+pi//3), x_(2)=8.0 sin (omega t+ pi//6), (b) x_(1)=3.0 cos omegat, x_(2)=5.0 cos (omegat+pi//4), x_(3)=6.0 sin omegat.

Assertion : For an oscillating simple pendulum, the tension in the string is maximum at the mean position and minimum at the extreme position. lt brgt Reason : The velocity of oscillating bob in simple harmonic motion is maximum at the mean position.

The period of oscillation of a particle in SHM is 4sec and its amplitude of vibration is 4cm . The distance of the particle 0.5s after passsing the mean position is

Potential energy of a particle at mean position is 4 J and at extreme position is 20 J. Given that amplitude of oscillation is A. Match the following two columns