Home
Class 11
PHYSICS
A uniform rod of length l is suspended f...

A uniform rod of length l is suspended from a point P. and the rod is made to undergo small oxcillations. Match the following

Text Solution

Verified by Experts

The correct Answer is:
`(A rarr t, B rarr t, C rarr s)`

`T=2pisqrt((I)/(mgl))`. Here , l is distance of point P from centre of mass.
When P is the centre , l=0. Therefore, `T=oo`, i.e., rod will not oscillate.
When P is end point , `I=(ml^(2))/(3)`
`therefore T=2pisqrt((l)/(3g))impliesT_("rod")=T_("pendulum")`
or `2pisqrt((2l)/(3g))=2pisqrt((L)/(g))`
or `L=(2l)/(3)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A uniform rod of length l is suspended by end and is made to undego small oscillations. Find the length of the simple pendulum having the time period equal to that of the rod.

A uniform rod of mass m and length l is suspended about its end. Time period of small angular oscillations is

A uniform thin rod of length l is suspended from one of its ends and is rotated at f rotations per second. The rotational kinetic energy of the rod will be

A uniform rod of length 2.0 m is suspended through an end and is set into oscillation with small amplitude under gravity. The time period of oscillation is approximately

A uniform rod of length 1.00 m is suspended through an end and is set into oscillation with small amplitude under gravity. Find the time period of oscillation.

A uniform rod of mass m and length l is suspended through a light wire of length l and torsional constant k as shown in figure. Find the time perid iof the system makes a. small oscillations in the vertical plane about the suspension point and b. angular oscillations in the horizontal plane about the centre of the rod.

A uniform rod of length 3L and mass m is suspended from a horizontal roof by two strings of length L and 2L as shown. Then the tension in the left string of length L is :