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A particle of mass 40 g executes a simpl...

A particle of mass 40 g executes a simple harmonic motion of amplitude 2.0 cm. If the time period is 0.20 s, find the total mechanical energy of the system.

A

`14.8xx10^(-3)J`

B

`7.9xx10^(-3)J`

C

`23.7xx10^(-3)J`

D

`3.9xx10^(-3)J`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) Total mechanical energy of the system,
`E=(1)/(2)momega^(2)a^(2)=(1)/(2)xx40xx10^(-3)((2pi)/(T))^(2)xx(2xx10^(2-))^(2)`
`=(1)/(2)xx40xx10^(-3)((3.14xx2)/(20))^(2)xx(2xx10^(-2))^(2)`
`3.94xx 10^(-3) J`
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