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If a simple pendulum is taken to place w...

If a simple pendulum is taken to place where g decreases by 2%, then the time period

A

increase by 5%

B

increase by 1%

C

increase by 2%

D

decrease by 5 %

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `T=2pisqrt((l)/(g)), "log"T="log"2pi+(1)/(2)"log"l-(1)/(2)"log"g`
Differentiating , `(dT)/(T)=0+(dl)/(2l)-(1)/(2)(dg)/(g)`
`because l`=constant
`therefore dl=0`
`100 xx (dT)/(T)=(-1)/(2)=(dg)/(g)xx100`
`=(-1)/(2)xx((-2)xx100)/(gxx100)=+1%` increase
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