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A simple pendulum executing S.H.M. is fa...

A simple pendulum executing S.H.M. is falling freely along with the support. Then

A

it does not oscillate at all

B

its periodic time increase

C

its periodic time decrease

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Time period of a simple pendulum,
`T=2pisqrt((l)/(g))`
For freely falling effective , g=0
So, `T=oo`
`therefore` Pendulum does not oscillate at all.
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