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There is no change in the volume of a wi...

There is no change in the volume of a wire due to change in its length on stretching. The poisson's ratio of the material of the wire is

A

`+0.50`

B

`-0.50`

C

0.25

D

`-0.25`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) We know that `(dV)/(V)=(1-2sigma)(dL)/(L)`
If `(dV)/(V)=0implies1-2sigma=0` or `sigma=(1)/(2)`
`therefore sigma=+0.50`
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Knowledge Check

  • There is no change in the volume of a wire due to the change in its length on stretching. The Poisson's ratio of the material of the wire is

    A
    `+(1)/(2)`
    B
    `-(1)/(2)`
    C
    `+(1)/(4)`
    D
    `-(1)/(4)`

  • It the volume of a wire remains constant when subjected to tensile stress, the value of Poisson's ratio of the material of the wire is

    A
    0.1
    B
    0.2
    C
    0.4
    D
    0.5

  • If the volume of a wire remains constant when subjected to tensile stress, the value of poisson's ratio of material of the wire is

    A
    0.1
    B
    0.2
    C
    0.4
    D
    0.5

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