Home
Class 11
PHYSICS
A wire suspended vertically from one of ...

A wire suspended vertically from one of its ends is Strached by attached a weight of `200 N` to the lower end . The weight straches the wire by `1 mm` . Then the elastic energy stored in the wire is

A

0.1 J

B

0.2 J

C

10 J

D

20 J

Text Solution

Verified by Experts

The correct Answer is:
B
(b) Energy stored by the spring
`U=(F^(2))/(2k)=(T^(2))/(2k)`
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY

    DC PANDEY|Exercise Chapter Exercise|73 Videos

  • ELASTICITY

    DC PANDEY|Exercise Match the columns|4 Videos

  • ELASTICITY

    DC PANDEY|Exercise Check point 12.2|15 Videos

  • CURRENT ELECTRICITY

    DC PANDEY|Exercise All Questions|434 Videos

  • ELECTROSTATICS

    DC PANDEY|Exercise Integer|17 Videos

Similar Questions

Explore conceptually related problems

A wire suspended vertically from one of itsends is strached by attached a weight of 200 N to the lower end . The weight streches the wire by 1 mm . Then the elastic energy stored in the wire is

A wire suspended vertically from one of the its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm. then the elastic energy stored in the wire is

A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 2mm. The elastic energy stored in the wire is

A wire suspended vertically from one end is stretched by attaching a weight of 20 N to the lower end. The weight stretches the wire by 1 mm. How much energy is gained by the wire ?

A wire suspended vertically from one of its ends is stretched by attaching a weight of 100 N to its lower end. What is the elastic potential energy stored in the wire, if the weight stretches the wire by 1.5 mm ?

A wire suspended vertically from one of its ends is stretched by attaching a weight of 20 N to its lower end. If its length changes by 1% and if the Young's modulus of the material of the wire is 2 xx 10^(11) N//m^(2) , then the area of cross section of the wire is

A wire of length 5 m is stretched by 1 mm by a force of 1 N. The value of energy (in mJ) stored in the wire is

A wire suspended vertically is stretched by a 20 kgf. applied to its free end. The increase in length of the wire is 2 mm. The energy stored in the wire is (g=10ms^(-2)) :